编写正则表达式以从一个任意字符串中查找另一个字符串中的模式

Question

我正在尝试使用正则表达式来查找在“field”中找到的类似的“保序”模式/单词，并使用它来查找“text”中的匹配项。我想编写这样一个正则表达式，它也会像下面的示例1一样找到部分匹配

也许，使单词可选是一种方法，但随后它开始匹配任意内容

我想让你们帮我写一个正则表达式，它取“field”并用它生成一个正则表达式，然后在“text”中找到该模式。部分匹配也可以。

两个字符串输入都可以是任何内容，正则表达式应该足够通用，可以处理任何内容

如果需要，请提出澄清问题！ 任何你能指出的我出错的观察/方向都会非常有帮助

def regexp(field, text):

    import re
    
    key = re.split('\W', field)
    regex= "^.*"
    for x in key:
        if len(x)>0:
            #regex += "("+x+")?"
            regex += x
            regex += ".*"

    regex = r'{}'.format(regex)
    pattern = re.compile(regex, re.IGNORECASE)
    matches = list(re.finditer(pattern, text))
    print(matches, "\n", pattern)

    if len(matches)>0:
        return True
    else:
        return False 

示例：

print(regexp("F1 gearbox: 0-400 m","f1 gearbox")) # this should match
#this is a partial match, my regex should be able to find this match

print(regexp("0-100 kmph" , "100-0 kmph")) # this should not match
#order of characters/words in my regex/text should match

print(regexp("F1 gearbox: 0-400 m","none")) # this should not match
#if i try use "(word)?" in my regex then everything becomes optional #and it starts to match random words like "none","sbhsuckjcsak", etc. #this obviously is not expected. 

print(regexp("Combined* (ECE+EUDC) (l/100 km)","combined ece eudc")) #this should match
#because its a partial match and special characters are not important #for my matching usecase

Answer 1

您的函数已经为您发布的示例返回了正确的值。您只需确定“文本”和“字段”的顺序。我还使代码更短（至少在我看来）更易于阅读：

def regexp(text, field):

    import re
    
    key = re.split('\W', field)
    regex = rf'^.*{".*".join(key)}'
    pattern = re.compile(regex, re.IGNORECASE)
    matches = re.findall(pattern, text)
    # print(matches, "\n", pattern)

    return len(matches)>0