在python中是否还有其他方法可以获得结果

Question

以下是输入：

CHPID PATH=(CSS(0,1,2),11),SHARED, NOTPART=((CSS(0),(BP0101),(BP0102),(=)),(CSS(1),(BP0112),(=)),(CSS(2),(BP0121),(=))),SWITCH=11,SWPORT=((11,31))

我希望得到以下结果：

输出：

 {'CSS(0)': ['(BP0101)', '(BP0102)'], 'CSS(1)': ['(BP0112)'], 'CSS(3)': ['(BP0121)']}

我的代码如下：

import re
content ='CHPID PATH=(CSS(0,1,2),11),SHARED, NOTPART=((CSS(0),(BP0101),(BP0102),(=)),(CSS(1),(BP0112),(=)),(CSS(3),(BP0121),(=))),SWITCH=11,SWPORT=((11,31))'
bb1 = "NOTPART" +".*"+ "\(=\)\)\)"
PART01 = re.compile(bb1)
matchb = PART01.search(content)
startxx = matchb.start() +9
endxx = matchb.end() -1
xxx = content[startxx:endxx]
bb00 = {}
bb01 = {}
larp00 = []
xxx1 = xxx.split(',')
for ii in range(len(xxx1)):
    if xxx1[ii][1:4] == 'CSS' :
        cs00 = xxx1[ii][1:]
    elif xxx1[ii][1:2] !=  '=':
        larp00.append(xxx1[ii])
    else:
        bb00 = {cs00:larp00}
        bb01.update(bb00)
        larp00=[]
print(bb01)

在python中是否有其他方法可以像使用正则表达式一样获得结果？如何解析数据

任何建议都将不胜感激

非常感谢

蔡简森

Answer 1

import re
content = 'CHPID PATH=(CSS(0,1,2),11),SHARED, NOTPART=((CSS(0),(BP0101),(BP0102),(=)),(CSS(1),(BP0112),(=)),(CSS(3),(BP0121),(=))),SWITCH=11,SWPORT=((11,31))'
r = re.compile(r'(CSS\(\d\).+?(?=.\(=\)))')
s = r.findall(content)

z = {j[0]: j[1:] for i in s for j in [i.split(',')]}
print(z)

{'CSS(0)': ['(BP0101)', '(BP0102)'], 'CSS(1)': ['(BP0112)'], 'CSS(3)': ['(BP0121)']}