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<p>我试图不使用<code>count()</code>或<code>count()</code>来计算每个字母
<code>dict()</code></p>
<p>我确实写了一些东西，但我的代码仍然有问题</p>
<pre><code>myString = []
#countList = [0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]
myString ="pynativepynvepynative"
countList = [len(myString)+1]
for i in range(len(myString)):
#print("Here 0")
for j in range(len(countList)):
#print("Here 1")
if i == countList[j]:
#print("Here 1.1")
countList[j+1] = (countList[j+1] + 1)
break
else:
#print("Here 2")
countList.append(myString[i])
countList.append(1)
break
print(countList)
</code></pre>
<p>预期产出：</p>
<pre><code>['p', 3, 'y', 3, 'n', 3, 'a', 2, 't', 2, 'i', 2, 'v', 3, 'e', 3]
</code></pre>
<p>实际产量：</p>
<pre><code>[22, 'p', 1, 'y', 1, 'n', 1, 'a', 1, 't', 1, 'i', 1, 'v', 1, 'e', 1, 'p', 1, 'y', 1, 'n', 1, 'v', 1, 'e', 1, 'p', 1, 'y', 1, 'n', 1, 'a', 1, 't', 1, 'i', 1, 'v', 1, 'e', 1]
</code></pre>
