“NoneType”对象不可iterable哪里有错误？

Question

我的目标是取三个(A, B, C)，计算三个“邻居”，然后将每个邻居的最大值输出到一个列表中

例如，(sqrt(6), 4*sqrt(3), 9*sqrt(2))的邻居是

(sqrt(3)*sqrt(2), 3*sqrt(2), 4*sqrt(3))

(4*sqrt(3), 35*sqrt(3)*sqrt(2), 9*sqrt(2))

(sqrt(3)*sqrt(2), 9*sqrt(2), 14*sqrt(3))

因此值14*sqrt(3), 36*sqrt(6), 4*sqrt(3)将是输出

当我尝试这个：

A = 1*sqrt(6)
B = 4*sqrt(3)
C = 9*sqrt(2)


def nbhs_1(triple):
    X = triple[0]
    Y = triple[1]
    Z = triple[2]

    print((X.canonicalize_radical(), (X * Y - Z).canonicalize_radical(), Y.canonicalize_radical()))


def nbhs_2(triple):
    X = triple[0]
    Y = triple[1]
    Z = triple[2]  

    print((Y.canonicalize_radical(), (Y * Z - X).canonicalize_radical(), Z.canonicalize_radical()))


def nbhs_3(triple):
    X = triple[0]
    Y = triple[1]
    Z = triple[2]

    print((X.canonicalize_radical(), Z.canonicalize_radical(), (X * Z - Y).canonicalize_radical()))

result_1 = nbhs_1((A, B, C))
result_2 = nbhs_2((A, B, C))
result_3 = nbhs_3((A, B, C))

print(result_1)
print(result_2)
print(result_3)

l = [max(result_1), max(result_2), max(result_3)]

我得到'NoneType' object is not iterable.

Answer 1

问题是您没有调用函数nbhs_1、nbhs_2和nbhs_3，而且这些函数也没有返回任何值

from math import sqrt

A=1*sqrt(6)
B=4*sqrt(3)
C=9*sqrt(2)
triple = (A, B, C)

def nbhs_1(triple):
    X=triple[0]
    Y=triple[1]
    Z=triple[2]
    return (X.canonicalize_radical(),(X*Y-Z).canonicalize_radical(),Y.canonicalize_radical())
def nbhs_2(triple):
    X=triple[0]
    Y=triple[1]
    Z=triple[2]  
    return (Y.canonicalize_radical(),(Y*Z-X).canonicalize_radical(),Z.canonicalize_radical())         
def nbhs_3(triple):
    X=triple[0]
    Y=triple[1]
    Z=triple[2]
    return (X.canonicalize_radical(),Z.canonicalize_radical(),(X*Z-Y).canonicalize_radical())

l=[max(nbhs_1(triple)),max(nbhs_2(triple)),max(nbhs_3(triple))]