一种检查字符串是否同时包含字符串和数字的方法

Question

我试图找到同时包含字符串和数字的单词。我试着做一些类似的事情：

string = "bear666 got sentenced 70 years in prison"

values = string.split()

for i in values:
    if i.isalpha() and i.isdigit():
        print(i)

但什么都没用。非常感谢您的帮助

我正在尝试将beaar666作为输出

Answer 1

试试这个：

string = "bear666 got sentenced 70 years in prison"
words = string.split(" ")

def hasNumbersAndAlphabets(inputString):
    return any(char.isdigit() for char in inputString) and any(c.isalpha() for c in inputString)

for word in words :
    if hasNumbersAndAlphabets(word) :
        print(word)

Answer 2

isalpha()和isdigit()检查整个单词是否仅由数字组成（或仅分别由字母组成）

通过迭代一个单词的所有字母来检查两者，如下所示：

string = "bear666 got sentenced 70 years in prison"

values = string.split()

for i in values:
    if any(char.isalpha() for char in i) and any(char.isdigit() for char in i):
        print(i)

Answer 3

尝试：

import re
string = "bear666 got sentenced 70 years in prison 666dog"
re.findall(r'(?:\d+[a-zA-Z]+|[a-zA-Z]+\d+)', string)

输出：

['bear666', '666dog']