如何在tkinter窗口中绘制networkx图形？

Question

我有两个函数可以在networkx中绘制不同的图形来绘制伦敦地铁上的列车线。它工作正常，但我想把它移到一个tkinter窗口。我有一套窗户，每列火车都有不同的框架。我只是不知道如何将这两个函数集成到窗口中！ 下面是我用来绘制图表的函数：

def drawPiccadilly(pos):
    #a dictionary declaring the labels for each node
    labels = {"Uxbridge(P)":"Uxbridge", "Rayners Lane(P)":"Rayners Lane", "Ealing Common(P)":"Ealing Common", "South Ealing(P)":"South Ealing", "Heathrow(P)":"Heathrow", "Hammersmith(P)":"Hammersmith", "Earls Court(P)":"Earls Court",
           "South Kensington(P)":"South Kensington", "Green Park(P)":"Green Park", "Piccadilly Circus(P)":"Piccadilly Circus", "Leicester Square(P)":"Leicester Square", "Holborn(P)":"Holborn", "Kings Cross St Pancras(P)":"Kings Cross St Pancras", "Finsbury Park(P)":"Finsbury Park", "Cockfosters(P)":"Cockfosters"}
    #a dictionary declaring the label positions
    PLabelPos = {"Uxbridge(P)":(-1300,1000), "Rayners Lane(P)":(-1100,1000), "Ealing Common(P)":(-1100,-100), "South Ealing(P)":(-1200,-400), "Heathrow(P)":(-1200,-750), "Hammersmith(P)":(-900,-250), "Earls Court(P)":(-700,-300),
           "South Kensington(P)":(-400,-600), "Green Park(P)":(-100,-300), "Piccadilly Circus(P)":(0,100), "Leicester Square(P)":(300,-200), "Holborn(P)":(500,500), "Kings Cross St Pancras(P)":(500,1000), "Finsbury Park(P)":(60,1200), "Cockfosters(P)":(600,1350)}
    #drawing the Piccadilly graph
    networkx.draw(Piccadilly, pos, node_color="purple", edge_color="blue", node_size = 100)
    networkx.draw_networkx_labels(Piccadilly, PLabelPos, labels, font_size=6)

我的窗口非常通用，只是一个容器和一些在框架之间切换的按钮。 这是我试图做的，但就是不起作用。它要么出现属性错误，要么“模块中不存在图形”

def drawPiccadilly():
    f = plt.Figure(figsize=(5,5), dpi=100)
    a = f.add_subplot(111)
    a.plot()
    a.draw(Piccadilly, node_color="purple", edge_color="blue", node_size = 100)

if __name__ == '__main__':
    app = Window()
    app.mainloop()