擅长:python、mysql、java
<p>我已经把它编好了,它给了我所有需要的组合</p>
<pre><code>bookies_all = [[1, 2], [3, 4], [5, 6]]
combos = []
count = 0
for outer in bookies_all:
for inner in bookies_all:
temp_list = [outer[0], inner[1]]
count += 1
combos.append(temp_list)
print(combos)
</code></pre>
<p>输出:[[1,2],<strong>[1,4]</strong>,<strong>[1,6]</strong>,<strong>[3,2]</strong>,[3,4],<strong>[3,6]</strong>,<strong>[5,2]</strong>,<strong>[5,4]</strong>,[5,6]]</p>
<p>粗体的组合就是我想要的。此代码适用于此示例</p>
<p>我将针对<code>bookies_all</code>列表具有更多值的场景进行测试</p>