下面的代码适用于PySide,但不适用于PySide2:
当动作被触发时(Ctrl+S),函数saveResults
被filename=False
调用,而不是像我预期的那样None
(PySide的情况是:可以通过切换导入语句进行测试)
我想知道行为是否发生了变化,
或者我的代码中要修复的东西?
(我知道我可以使用lambda技巧,我更好奇的是插槽语法还是连接需要精确性)
import sys
# PySide2 won't pop up the QFileDialog
from PySide2.QtGui import *
from PySide2.QtWidgets import *
from PySide2.QtCore import Slot
# # PySide works fine:
# from PySide.QtGui import *
# from PySide.QtCore import Slot
class MyWindow(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
self.fileMenu = self.menuBar().addMenu("&File")
act = QAction("Save results...", self)
act.triggered.connect(self.saveResults) # <--- should call saveResults(None)
#act.triggered.connect(lambda: self.saveResults(None)) # fixes the issue
act.setShortcuts([QKeySequence.Save])
self.fileMenu.addAction(act)
@Slot()
def saveResults(self, filename=None):
print ('Calling saveResults, filename is', filename)
if filename is None:
(filename, selectedfilter) = QFileDialog.getSaveFileName(self,"Save results as ", ".", "NPY Files (*.npy);;Image files (*.png *.tif *.tiff *.bmp);;All files (*)")
# ... exit if cancel clicked
# finally save the file:
print('Saving', filename)
qt_app = QApplication(sys.argv)
app = MyWindow()
app.show()
qt_app.exec_()
这似乎是一个bug,解决方法是通过关键字触发连接:
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