Python输入函数，打印

Question

我正在尝试创建一个简单的函数，python将根据您输入的年份计算年龄。我试过好几种方法，但都不走运

抱歉，我是个新手

ame = input(" Enter your name: ")

age = input(" When were you born?: ")

print("Hello " + name + "! You are " + input (2021 - age)

Answer 1

以下是您可以执行的操作：将age转换为integer，然后从2021中减去它

ame = input(" Enter your name: ")
age = input(" When were you born (year) ?: ")
print("Hello " + name + "! You are ",2021- int(age))

Answer 2

让我们逐行查看您提供的代码示例

name = input(" Enter your name: ")

此行创建一个名为name的变量，并将其分配给内置函数input的返回值

age = input(" When were you born? ")

这也是一样的，只是年龄不同。请注意，这存储的是字符串（某些字符）而不是int。您可能希望将其转换为以下格式：

age = int(age)

接下来，您将尝试打印：

print("Hello " + name + "! You are " + input (2021 - age)

但是为了弄清楚打印什么，Python必须计算input(2021-age)的返回。（请记住，在代码中age是一个字符串；不能减去字符串和整数）

这里还有一个问题-您正在提示并再次等待输入，但不需要这样做。您已经将用户的输入存储在age和name变量中

所以你真正想做的是：

print("Hello, " + name + "! You are " + 2021 - age )

现在，如果你想更简洁一点，你也可以这样做：

print(f"Hello, {name}! You are {2021 - age}")

Answer 3

import datetime

# get the year so it works all the time.
year = datetime.datetime.today().year
name = input(" Enter your name: ")
birth_year = input(" When were you born (year) ?: ")

# calclute the age
age = year - int(birth_year)

print("Hello " + name + "! You are ", age)

还有其他一些打印方式可能看起来更干净：

print(f'Hello {name}! You are {age}')

或

print("Hello {0}! You are {1}".format(name, age))

使其成为功能：

import datetime

def age_cal(birth_year):
    # get the year so it works all the time.
    year = datetime.datetime.today().year
    return year - int(birth_year)

if __name__ == "__main__":
    name = input(" Enter your name: ")
    birth_year = input(" When were you born (year) ?: ")
    age = age_cal(birth_year)

    print("Hello {0}! You are {1}".format(name, age))