擅长:python、mysql、java
<p>您不需要使用循环,只需使用列表中相应字典的索引即可:</p>
<pre><code>list_of_dicts = [
{
'Name': 'John',
'Surname': 'Johnson'
},
{
'Number': 123,
'Birthday': 1960
}
]
name = list_of_dicts[0]['Name']
birth_year = list_of_dicts[1]['Birthday']
print(f"{name}'s birth year is {birth_year}")
</code></pre>
<p><strong>输出:</strong></p>
<pre><code>John's birth year is 1960
</code></pre>