我有一个正在进行的项目,它引用了其他类中的几个类
代码:
try:
from PyQt5 import QtWidgets
from PyQt5.QtWidgets import QApplication, QMainWindow, QPushButton
except:
input('Please install PyQt5 before using the GUI system. (press enter to close)')
exit()
class app(QApplication):
def __init__(self):
super(app, self).__init__([])
print('running')
andGate = gate()
andGate.config('and', 2)
def initUI(self):
newAndBtn = QPushButton(self)
newOrBtn = QPushButton(self)
newXorBtn = QPushButton(self)
def newAndGate(self):
pass
class gate():
gateType = 'none'
_in = []
_out = pinOut()
def _init__(self):
_in.append(pinIn())
_in.append(pinIn())
pass
def config(self, gateType, inputTargets):
#just some safety checks
if gateType not in supportedGates:
return False
self.gateType = gateType
if type(inputTargets) is not list:
return False
for i in inputTargets:
if type(i) is not pinOut:
return False
self.gateType = gateType
for i in range(len(self._in)):
self._in[i].point(inputTargets[i])
def update(self):
if _in[0].fetch() and _in[1].fetch():
_out.set(True)
else:
_out.set(False)
print("update for {}".format(self))
class pinIn():
value = True
reference = None
def __init__(self):
pass
def point(target):
if type(target) is not connOut:
return False
reference = target
def fetch():
self.value = reference.value
return self.value
class pinOut():
value = False
def __init__(self):
pass
def set(self, newValue):
if type(newValue) is not bool:
return False
self.value = newValue
创建app()类的实例时,会得到一个回溯:
Traceback (most recent call last):
File "C:\Users\ccronk22\Documents\Python_Scripts\Logic\run.py", line 1, in <module>
import main
File "C:\Users\ccronk22\Documents\Python_Scripts\Logic\main.py", line 8, in <module>
class app(QApplication):
File "C:\Users\ccronk22\Documents\Python_Scripts\Logic\main.py", line 23, in app
class gate():
File "C:\Users\ccronk22\Documents\Python_Scripts\Logic\main.py", line 26, in gate
output = pinOut()
NameError: name 'pinOut' is not defined
我曾尝试将pinIn和pinout类移到gate类中,然后将它们全部移到app类中,但这些都不起作用。在此之前,我一直将_-in声明为包含两个pinIn实例的列表,但得到了相同的错误
为什么gate类看不到pinIn和pinout类
类
pinOut
在引用它之后定义为:将
pinOut
的定义移到gate
的定义之前,或者更好地将其设置在__init__
:您应该更喜欢在
__init__
中初始化东西的原因是,这样可以避免在多个实例之间共享状态,这很可能是您想要避免的相关问题 更多 >
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