计算字符串中的字符数

Question

所以我试着计算ancrawler，返回带空格和不带空格的字符数，以及“死星”的位置，并在报告中返回。我也数不清。请帮忙！在

anhCrawler = """Episode IV, A NEW HOPE. It is a period of civil war. \
Rebel spaceships, striking from a hidden base, have won their first \
victory against the evil Galactic Empire. During the battle, Rebel \
spies managed to steal secret plans to the Empire's ultimate weapon, \
the DEATH STAR, an armored space station with enough power to destroy \
an entire planet. Pursued by the Empire's sinister agents, Princess Leia\
races home aboard her starship, custodian of the stolen plans that can \
save her people and restore freedom to the galaxy."""

theReport = """
This text contains {0} characters ({1} if you ignore spaces).
There are approximately {2} words in the text. The phrase
DEATH STAR occurs and starts at position {3}.
"""

def analyzeCrawler(thetext):
numchars = 0
nospacechars = 0
numspacechars = 0
anhCrawler = thetext
word = anhCrawler.split()
for char in word:
    numchars = word[numchars]
    if numchars == " ":
        numspacechars += 1
anhCrawler = re.split(" ", anhCrawler)
for char in anhCrawler:
    nospacechars += 1
numwords = len(anhCrawler)
pos = thetext.find("DEATH STAR")
char_len = len("DEATH STAR")
ds = thetext[261:271]
dspos = "[261:271]"

return theReport.format(numchars, nospacechars, numwords, dspos)
print analyzeCrawler(theReport)

Answer 1

你想得太多了。

字符串中的字符数（返回520）：

len(anhCrawler)

字符串中非空白字符的数目（使用split与使用split一样自动删除空白，join创建一个没有空格的字符串）（返回434）：

^{pr2}$

“发现死亡之星的位置”（261）：

anhCrawler.find("DEATH STAR")

Answer 2

在这里，您得到了函数的简化版本：

import re

def analyzeCrawler2(thetext, text_to_search = "DEATH STAR"):

    numchars = len(anhCrawler)
    nospacechars = len(re.sub(r"\s+", "", anhCrawler))
    numwords   = len(anhCrawler.split())
    dspos      =  anhCrawler.find(text_to_search)

    return theReport.format(numchars, nospacechars, numwords, dspos)



print analyzeCrawler2(theReport)


This text contains 520 characters (434 if you ignore spaces).
There are approximately 87 words in the text. The phrase
DEATH STAR occurs and starts at position 261.

我认为技巧部分是从字符串中删除空格并计算非空格字符数。这可以通过使用正则表达式来实现。其余的应该是不言而喻的。在

Answer 3

首先，您需要缩进函数内部的代码。第二。。。您的代码可以简化为以下内容：

theReport = """
    This text contains {0} characters ({1} if you ignore spaces).
    There are approximately {2} words in the text. The phrase
    DEATH STAR is the {3}th word and starts at the {4}th character.
"""

def analyzeCrawler(thetext):

    numchars = len(anhCrawler)
    nospacechars = len(anhCrawler.replace(' ', ''))
    numwords = len(anhCrawler.split())

    word = 'DEATH STAR'
    wordPosition = anhCrawler.split().index(word)
    charPosition = anhCrawler.find(word)

    return theReport.format(
        numchars, nospacechars, numwords, wordPosition, charPosition
    )

我修改了最后两个format参数，因为它不清楚你所说的dspos是什么意思，尽管这可能很明显，我没有看到它。在任何情况下，我改为包含单词和字符位置。你可以决定你真正想要包括哪一个。在