将RSA解密从PyCrypto迁移到PyCryptodome

2024-10-01 00:31:05 发布

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使用PyCrypto库,以下代码打印127

from Crypto.PublicKey import RSA
import base64

# Private key in tuple form (obscured for privacy)
key = [1, 1, 1]

bk = "zJuG60z9Iv..." # (obscured for privacy)

privatekey = RSA.construct(key)
result = privatekey.decrypt(base64.b64decode(bk))
print(len(result))

据我所知,这将相当于使用PyCryptodome。但是,结果值的长度仅为16,表示可能存在解密错误

from Crypto.PublicKey import RSA
from Crypto.Cipher import PKCS1_v1_5
import base64

# Private key in tuple form (obscured for privacy)
key = [1, 1, 1]

bk = "zJuG60z9Iv..." # (obscured for privacy)

privatekey = RSA.construct(key)
cipher = PKCS1_v1_5.new(privatekey)
result = cipher.decrypt(base64.b64decode(bk), None)
print(len(result))

我相信这是因为我的密文使用了RSA。有人知道我如何用PyCryptodome或其他维护的库解密此值吗


Tags: keyinfromimportforresultprivatecrypto
1条回答
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1楼 · 发布于 2024-10-01 00:31:05

PyCryptodome没有提供一种内置的方法来解密教科书中的RSA,但是可以使用标准库中的模幂运算来解密

from Crypto.PublicKey import RSA
import base64

# Private key in tuple form (obscured for privacy)
key = [1, 1, 1]

bk = "zJuG60z9Iv..." # (obscured for privacy)

privatekey = RSA.construct(key)
ciphertext = base64.b64decode(bk)
ct_int = int.from_bytes(ciphertext, 'big')
pt_int = pow(ct_int, privatekey.d, privatekey.n)
plaintext = pt_int.to_bytes(privatekey.size_in_bytes(), 'big').lstrip(b'\x00')
print(len(plaintext))

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