擅长:python、mysql、java
<p>听起来递归应该能够解决这个问题:</p>
<pre><code>a = [1,2,3]
b = [[1,2,3], [4,5,6]]
c = [[[1,2,3], [4,5,6]], [[7,8,9], [10,11,12]]]
f = lambda x : x+1
def apply(iterable, f):
# suggestion by Jérôme:
# from collections.abc import Iterable and use
# isinstance(iterable, collections.abc.Iterable) so it works for tuples etc.
if isinstance(iterable, list):
# apply function to each element
return [apply(w, f) for w in iterable]
else:
return f(iterable)
print(apply(a, f)) # [2,3,4]
print(apply(b, f)) # [[2,3,4],[5,6,7]]
print(apply(c, f)) # [[[2,3,4],[5,6,7]],[[8,9,10],[11,12,13]]]
</code></pre>