如何在windows中使用Socket将消息从Android发送到python应用程序

Question

我试图在windows中将消息从android应用程序发送到python应用程序，但它不起作用

Android应用程序运行良好，但在windows中使用python创建的客户端未启动。它显示错误：-回溯（最近一次调用）： 文件“client.py”，第14行，在 s、 连接（（socket.gethostname（），9876）） ConnectionRefusedError:[WinError 10061]无法建立连接，因为目标计算机主动拒绝了它

这是我的client.py文件

#!/usr/bin/env python
# coding: utf-8

# In[1]:


import socket


# In[2]:


s=socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((socket.gethostname(), 9876))


# In[ ]:

while True:
    msg = s.recv(1024)
    print(msg.decode("utf-8"))

这是我在android中的messageSender.java

package com.example.sockets;

import android.os.AsyncTask;

import java.io.DataOutputStream;
import java.io.IOException;
import java.io.PrintWriter;
import java.net.Socket;

public class MessegeSender extends AsyncTask<String,Void,Void> {
    Socket socket;
    DataOutputStream dataOutputStream;
    PrintWriter printWriter;


    @Override
    protected Void doInBackground(String... strings) {
        String message=strings[0];

        try {
            socket = new Socket("192.168.1.6",9876);
            printWriter= new PrintWriter(socket.getOutputStream());
            printWriter.write(message);
            printWriter.flush();
            printWriter.close();
            socket.close();

        } catch (IOException e) {
            e.printStackTrace();
        }

        return null;
    }
}

这是我在android中的Mainactivity.java文件

package com.example.sockets;

import androidx.appcompat.app.AppCompatActivity;

import android.os.Bundle;
import android.view.View;
import android.widget.EditText;
import android.widget.Toast;

public class MainActivity extends AppCompatActivity {

    EditText editText;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        editText=(EditText) findViewById(R.id.msgBox);
    }

    public void sendMsg(View view)
    {
        Toast.makeText(this, "Function is running", Toast.LENGTH_SHORT).show();
        MessegeSender messegeSender =new MessegeSender();
        messegeSender.execute(editText.getText().toString());
    }
}

Answer 1

如果您希望通过套接字将android应用程序连接到python，则在android中执行与上述相同的操作，但通过以下方式更改python文件-

#Imports Modules
import socket
import time

listensocket = socket.socket()
Port = 9876
maxConnections = 2
IP = socket.gethostname() #Gets Hostname Of Current Macheine

listensocket.bind(('',Port))

#Opens Server
listensocket.listen(maxConnections)
print("Server started at " + IP + " on port " + str(Port))

#Accepts Incoming Connection
# (clientsocket, address) = listensocket.accept()
# print("New connection made!")

# running = True


#Main
while True:
    (clientsocket, address) = listensocket.accept()
    message = clientsocket.recv(1024).decode() #Receives Message
    print(message) #Prints Message

    # if not message == "":
    #    print(message) #Prints Message
      
    #Closes Server If Message Is Nothing (Client Terminated)
    # elif message =="":
    #     clientsocket.close()
    #     # running = False