一个彩票程序的2D Python列表

Question

我正在创建一个乐透计划，在那里它可以抽取8个数字，并检查它们是否和100个乐透玩家的数字匹配。我已经创建了随机生成8个数字并将其存储在列表中的部分，但是我不知道如何在python中创建一个2D列表来存储用户随机生成的数字及其ID

例如，2D列表应该如下所示

Player ID | PlayerNumber
 1        | 2 3 4 5 6 7 4 23
 2        | 14 12 14 30 0 13 25
 3        | 21 30 2 22 23 14 19 12
 4        | 21 12 22 30 24 25 28 15

8 numbers winning numbers are from a pool of 0 - 30 numbers
the Player ID pool is 1 - 100 meaning 100 players
the Lotto number pool is 0 - 30

我创建的部分绘制了8个中奖号码，但我不知道如何创建上表

import random

def generateRandomNumber():
    randomNumber = random.randint(0,30) #can return numbers between 0 and 30 including 0 and 30
    return randomNumber#return Random numbers

def drawWinningLotteryNumber():#this function draws the winning numbers
    lotteryDrawNumbers = []#list containner for the generated lottery numbers
    for currentLotteryNumber in range(8):#for loop to keep generating for 8 counts
        randomNumber = generateRandomNumber()# call funtion to generate random numbers
        lotteryDrawNumbers.append(randomNumber)# add to the back of the list

    return lotteryDrawNumbers#return the list
    
def printWinningLotteryNumber(lotteryDrawNumbers):#ths function prints the draw numbers
    for currentLotteryNumberIndex in range (len(lotteryDrawNumbers)):#for loop to run the print funtion for the length of the list
        print(lotteryDrawNumbers[currentLotteryNumberIndex], end = " ")#prints the numbers

def draw():# this funtion brings to gether the draw funtion
    
    lotteryNumbers = drawWinningLotteryNumber()#call function to draw winning numbers
    print ("The 8 lottery number for today are :")
    printWinningLotteryNumber(lotteryNumbers)#call funtion to print the generated numbers

def generateID():#this function creates the lotto players and their numbers
    i = 0
    players = []

    for currentPlayers in range(100):
        i = i + 1
        players.append(i)

    for currentPlayerIndex in range(len(players)):
        print(players[currentPlayerIndex])

generateID()

draw()

Answer 1

可能是这样的：

from random import choices

number_of_players = 4

draws = [choices(range(0, 30), k=8) for _ in range(number_of_players)]

print("Player ID | Draw")
for player_id, draw in enumerate(draws, start=1):
    print(f"{player_id:<10}|", *draw)

输出：

Player ID | Draw
1         | 6 1 5 9 16 29 12 17
2         | 25 21 8 22 5 10 28 26
3         | 8 1 18 6 18 20 1 0
4         | 28 9 28 2 21 23 17 1
>>> 

我建议使用random.choices从可能的数字集合/总体中选择您的随机数。如果您使用random.randint生成数字，您可能会在给定的抽奖中多次出现相同的数字（据我所知，任何给定编号的彩票球在真正的抽奖中不会出现多次）

Answer 2

您可以使用字典players将ID与数字列表相关联。试试这个：

def generateID():#this function creates the lotto players and their numbers
    players = {}

    for player_id in range(1, 11):
        player_list = []
        for i in range(8):
            player_list.append(generateRandomNumber())
        players[player_id] = player_list

    for player_id in players:
        print("Player {} has numbers {}".format(player_id, players[player_id]))

输出：

Player 1 has numbers [24, 23, 29, 16, 14, 1, 24, 0]
Player 2 has numbers [13, 7, 13, 8, 11, 2, 14, 11]
Player 3 has numbers [1, 17, 2, 30, 8, 10, 6, 18]
Player 4 has numbers [23, 0, 0, 9, 15, 12, 5, 20]
Player 5 has numbers [7, 5, 1, 0, 13, 10, 8, 11]
Player 6 has numbers [24, 6, 2, 15, 18, 9, 6, 29]
Player 7 has numbers [17, 9, 3, 30, 29, 28, 5, 19]
Player 8 has numbers [23, 30, 9, 12, 23, 19, 15, 5]
Player 9 has numbers [15, 11, 3, 22, 20, 6, 24, 4]
Player 10 has numbers [14, 29, 6, 13, 22, 11, 25, 20]