在python中创建按钮

Question

我正在尝试为有特殊需要的儿童制作一个互动游戏，你点击一个按钮，它就会移动照片。但是，我需要一些帮助，因为当我运行代码时，当您单击按钮时，控制台会打印“…”，当您离开按钮时，控制台不会打印。一切都在那里工作。无论您在按钮上方或下方单击什么位置，它都会将其识别为按钮。因此，它无法区分y坐标列不是按钮坐标的一部分。谢谢你的帮助！请参阅照片：[游戏窗口][1]。。。 代码：

import pygame
import random

pygame.init()
#define variables
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GREEN = (0, 255, 0)
RED = (255, 0, 0)
background_colour = (255, 255, 255)
(width, height) = (700, 500)
x = 250
y = 100
mpos = pygame.mouse.get_pos()
mpress = pygame.mouse.get_pressed()
Button1 = 'photos/buttonCow.png'
Button2 = 'photos/buttonDuck.png'
Button3 = 'photos/buttonHorse.png'
Button4 = 'photos/buttonSheep.png'

imageOption1 = pygame.image.load(Button1)
imageOption2 = pygame.image.load(Button2)
imageOption3 = pygame.image.load(Button3)
imageOption4 = pygame.image.load(Button4)


screen = pygame.display.set_mode((width, height))
pygame.display.set_caption('Game!')
screen.fill(background_colour)
running = True


def buttons():
    if pygame.mouse.get_pos() >= (200, 400):
        if pygame.mouse.get_pos() <= (260, 430):
            print("horse")
    if pygame.mouse.get_pos() >= (300, 400):
        if pygame.mouse.get_pos() <= (360, 430):
            print("duck")
    if pygame.mouse.get_pos() >= (400, 400):
        if pygame.mouse.get_pos() <= (460, 430):
            print("cow")
    if pygame.mouse.get_pos() >= (500, 400):
        if pygame.mouse.get_pos() <= (560, 430):
            print("sheep")


def displayOptions():
    screen.blit(imageOption1, (400, 400))
    screen.blit(imageOption2, (300, 400))
    screen.blit(imageOption3, (200, 400))
    screen.blit(imageOption4, (500, 400))


def whichAnimalFunc():
    whichAnimal = random.randint(0, 4)
    if whichAnimal == 1:
        image = pygame.image.load('photos/cow.png')
        screen.fill(WHITE)
        screen.blit(image, (x, y))
        displayOptions()
        pygame.display.update()
    if whichAnimal == 2:
        image = pygame.image.load('photos/duck.png')
        screen.fill(WHITE)
        screen.blit(image, (x, y))
        displayOptions()
        pygame.display.update()
    if whichAnimal == 3:
        image = pygame.image.load('photos/horse.png')
        screen.fill(WHITE)
        screen.blit(image, (x, y))
        displayOptions()
        pygame.display.update()
    elif whichAnimal == 4:
        image = pygame.image.load('photos/sheep.jpg')
        screen.fill(WHITE)
        screen.blit(image, (x, y))
        displayOptions()
        pygame.display.update()
    else:
        pygame.QUIT


while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False  # allows quit button to work
        if event.type == pygame.MOUSEBUTTONDOWN:
            pos = pygame.mouse.get_pos()
            print(pos)
            buttons()
            whichAnimalFunc()
            pygame.display.update()```



  [1]: https://i.stack.imgur.com/xDCa0.png

Answer 1

你不能只说pygame.mouse.get_pos() >= (200, 400)，你必须说：

mouse_pos = pygame.mouse.get_pos()
if mouse[0] >= 200 and mouse[1] >= 400:
   # hovering

Answer 2

你必须单独检查坐标。不要忘记按钮的大小：

mx, my = pygame.mouse.get_pos()
if mx >= 200 and my >= 400 and mx < 200 + imageOption3.get_width() and my < 400 + imageOption3.get_height():
    print("horse")

此外，您还可以使用列表缩短整个过程（如果您不熟悉对象）：

gameData = [
# (buttonX, buttonY, name) - will be extended by button image
[400, 400, 'Cow'],
[500, 400, 'Duck'],
#...
]

# load buttons:
for item in gameData:
    item.append(pygame.image.load("photos/button%s.png"%item[2]))

def displayOptions():
    for button in gameData:
        screen.blit(button[3], (button[0], button[1]))

def buttons():
    mx, my = pygame.mouse.get_pos()
    for button in gameData:
        bx, by = button[0], item[1]
        bw, bh = button[3].get_size()
        if mx >= bx and my >= by and mx < bx+bw and my < by+bh:
            print(button[2])

# etc.