擅长:python、mysql、java
<p>您的<code>locateLargest</code>函数可以简单得多:</p>
<pre><code>def locateLargest(matrix):
largest_num = None
row = None
col = None
for row_idx, row in enumerate(matrix):
for col_idx, num in enumerate(row):
if num > largest_num or largest_num is None:
largest_num = num
row = row_idx
col = col_idx
return (largest_num, row, col)
</code></pre>
<p>此函数返回最大的数字,以及列和行索引(基于0的索引)。在</p>
<p>示例:</p>
^{pr2}$