从wav文件python中提取频率

2024-10-03 11:22:27 发布

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我对python很熟悉,但对numpy还是新手,所以如果我错了,请原谅我。在

我试着读一个有多个频率的.wav文件(以静音分隔)。到目前为止,我已经能够读取值并找到文件中有声音的各个部分。然后,我试图找到离散余弦变换并从中计算出频率(参考文献:how to extract frequency associated with fft values in python

但是,我得到一个错误:

index 46392 is out of bounds for axis 0 with size 25

我的代码是:

import wave
import struct
import numpy as np

def isSilence(windowPosition):
    sumVal = sum( [ x*x for x in sound[windowPosition:windowPosition+windowSize+1] ] )
    avg = sumVal/(windowSize)
    if avg <= 0.0001:
        return True
    else:
        return False

#read from wav file
sound_file = wave.open('test.wav', 'r')
file_length = sound_file.getnframes()
data = sound_file.readframes(file_length)
sound_file.close()
#data = struct.unpack("<h", data)
data = struct.unpack('{n}h'.format(n=file_length), data)
sound = np.array(data)
#sound is now a list of values

#detect silence and notes
i=0
windowSize = 2205
windowPosition = 0
listOfLists = []
listOfLists.append([])
maxVal = len(sound) - windowSize
while True:
    if windowPosition >= maxVal:
        break
    if not isSilence(windowPosition):
        while not isSilence(windowPosition):
            listOfLists[i].append(sound[windowPosition:windowPosition+ windowSize+1])
            windowPosition += windowSize
        listOfLists.append([]) #empty list
        i += 1
    windowPosition += windowSize

frequencies = []
#Calculating the frequency of each detected note by using DFT
for signal in listOfLists:
    if not signal:
        break
    w = np.fft.fft(signal)
    freqs = np.fft.fftfreq(len(w))
    l = len(signal)

    #imax = index of first peak in w
    imax = np.argmax(np.abs(w))
    fs = freqs[imax]

    freq = imax*fs/l
    frequencies.append(freq)

print frequencies

编辑:回溯如下:

^{pr2}$

Tags: ofinfftdatasignalifnpfile
1条回答
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1楼 · 发布于 2024-10-03 11:22:27

问题是我假设listOfLists实际上是一个列表列表,但实际上它是一个列表列表列表。行:

        listOfLists[i].append(sound[windowPosition:windowPosition+ windowSize+1])

每次都会附加一个列表,但我假设它是将元素附加到现有列表中。在

例如,如果listOfLists是:

^{pr2}$

然后,listOfLists[0].append([4,5,6])将给出:

[ [ [1,2,3],[4,5,6] ] ]

但我期待着:

[ [1,2,3,4,5,6] ]

用下面的代码替换有问题的行对我很有用:

for v in sound[windowPosition:windowPosition+windowSize+1]:
            listOfLists[i].append(v)

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