zlib TypeError: a bytes-like object is required, not str

Question

我用这段代码来编码和压缩文本。但它不能正常工作：

Traceback (most recent call last): File "E:\SOUND.py", line 114, in <module>
unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str' 

你能帮我吗？在

^{pr2}$

此代码不会解压缩zlib压缩文本。在

所以编码很有效。在

我的问题是，当我得到编码字符串并压缩它时，我无法解压缩它。 它应该如何工作：

1>s = input('some text')
2>if len(s) > 200: s = str(zlib.compress(s.encode('utf-8'))) 
3>encoding it with str2hex()
4>decode it with hex2str()
5>str(zlib.decompress(unhexs).encode('utf8'))  <---------- HERE

我不能正确地解压因为得到这个：

下一个控制台转储

Python 3.7.0 (v3.7.0:1bf9cc5093, Jun 27 2018, 04:06:47) [MSC v.1914 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> 
========================= RESTART: E:\SOUND.py =========================
dghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjghdghlkdushfgkjdsfhglkjhsdfgjhdskfjhgkdsfhgkjdhfgkjsdhfgjkhsdkjfghlkjsdhgkjhsdfjghdksjhgkjsdhgkjhsdfkjghdskfjghkdjgh
b'x\x9c\xed\x8d\xb1\r\xc0@\x08\x03\x97\xb5\xb0e\x7f\x87\xb2\x7f\x9eO\x93\x05\xd2\xa5\x02\x1d>\x0cj\x05W\xab\x18\xa3K\\\xb1\x1aE\x0b\x9d\xb2\x98\x83\xf7\xf5dz\x86\xb3#q\x8d<\x84\x8fc\n\xe9Q^0C\xe7\x13\x15\xcc\xfe7~\xd0x\x03\x88\x05\xbb\x9d'
6227785c7839635c7865645c7838645c7862315c725c786330405c7830385c7830335c7839375c7862355c786230655c7837665c7838375c7862325c7837665c7839654f5c7839335c7830355c7864325c7861355c7830325c7831643e5c7830636a5c783035575c7861625c7831385c7861334b5c5c5c7862315c783161455c7830625c7839645c7862325c7839385c7838335c7866375c786635647a5c7838365c78623323715c7838643c5c7838345c783866635c6e5c786539515e30435c7865375c7831335c7831355c7863635c786665377e5c786430785c7830335c7838385c7830355c7862625c78396427
compressed
Traceback (most recent call last):
  File "E:\SOUND.py", line 114, in <module>
    unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
TypeError: a bytes-like object is required, not 'str'

Answer 1

你在这里看到的例外情况是：

unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
    TypeError: a bytes-like object is required, not 'str'

引发，因为zlib.decompress需要{}。这很容易通过改变

^{pr2}$

到

unhexsring = hex2str(hexstring)    # -> bytes

但是，这会导致一个新的错误：

unhexsring = zlib.decompress(unhexsring)
    zlib.error: Error -3 while decompressing data: incorrect header check

这是因为这句话：

hexstring = str(zlib.compress(hexstring.encode('utf-8')))

对bytes实例调用str不会将bytes转换为str，而是将字节repr转换为str。在

>>> bs = 'Hello World'.encode('utf-8')
>>> print(repr(bs))
b'Hello World'
>>> s = str(bs)
>>> print(repr(s))
"b'Hello World'"    # <- note the b....

str转换在压缩数据的前面插入了一个'b'，从而损坏了头。现在让我们将hexstring保留为bytes对象

hexstring = zlib.compress(hexstring.encode('utf-8'))

但现在代码又引发了另一个例外：

return binascii.hexlify(bytes(str.encode(s)))
    TypeError: descriptor 'encode' requires a 'str' object but received a 'bytes'

s现在是一个bytes对象，因此不需要尝试转换它（注意，str.encode无论如何都返回{}，因此即使s是字符串，bytes调用也是多余的）。在

{cd16>变成了

def str2hex(s):
    return binascii.hexlify(s)

现在又出现了另一个错误：

unhexsring = str(zlib.decompress(unhexsring).encode('utf8'))
    AttributeError: 'bytes' object has no attribute 'encode'

zlib.decompress的输出是一个bytes对象，因此它已经被编码（假设它是一个字符串开头）。您想对其进行解码以获得str：

unhexsring = zlib.decompress(unhexsring).decode('utf8')

这是可以作为脚本从命令提示符下运行的代码版本：

import binascii
import random
import string
import zlib,gzip

import zlib,gzip

def str2hex(s):
    return binascii.hexlify(s)


def hex2str(h):
    return binascii.unhexlify(h)

def main():
    # I don't want to type 200+ chars to test this :-)
    hexstring = ''.join(random.choice(string.ascii_letters) for _ in range(201))
    if len(hexstring) > 200:
        hexstring = zlib.compress(hexstring.encode('utf-8'))
        print(hexstring)
    hexstring = str2hex(hexstring)
    ph = str(hexstring.decode('utf-8'))
    print(ph)

    #decompressing text
    unhexsring = hex2str(hexstring)
    if 'x' in str(unhexsring):
        print('compressed')
        unhexsring = zlib.decompress(unhexsring).decode('utf8')
    print(unhexsring)

if __name__ == '__main__':
    main()

Answer 2

很有趣的问题，我认为你应该把这个去掉

hexstring = input()

代码的简单示例

^{pr2}$