Python骰子游戏指南

Question

在我的Python类中，我们现在正在做远程项目，最近的一个项目让我感到困惑。我们将创建一个骰子游戏，其功能如下： 1.输入您的下注金额 2.然后掷骰子，结果设为“点” 3.再次掷骰子，7或11导致赢，2、3或12导致输，任何其他结果导致重新掷骰

我可以写这段代码，但我们已经得到了一个框架脚本，必须使我们的解决方案适合它。由于我在函数方面的经验有限，我很难做到这一点。我曾试着自学，但这本骨架剧本真的让我很反感。我非常感谢您的帮助，如果这个问题在这里不合适，我深表歉意。我不是在找人帮我写解决方案，只是一些指导。提前谢谢

以下是基本脚本：

import random

def enterBet(): # returns amount bet (1-1000)

def rollTheDice():  # returns die1, die2

def setPoint(bet):  # returns the outome of the game and the point

def playDice(bet, point):  # returns the outcome

OUTCOME_WIN = 1
OUTCOME_LOSE = 2
OUTCOME_REROLL = 3

def main():

    bet = enterBet()
    outcome, point = setPoint(bet)

    while outcome == OUTCOME_REROLL:
        outcome = playDice(bet,point)

if __name__ == "__main__":
    main()

以下是我迄今为止最好的尝试：

import random

def enterBet(): # returns amount bet (1-1000)
    int(input("Please Enter Your Bet: "))

def rollTheDice():  # returns die1, die2
    die1 = random.randint(1, 6)
    die2 = random.randint(1, 6)
    return die1, die2

def setPoint(bet):  # returns the outome of the game and the point
    rollTheDice()
    point = die1 + die2
    print('You rolled a ' + point + '.')
    print('This is the new point.')
    return point, outcome

def playDice(bet, point):  # returns the outcome
    print('Point is: ' + point )
    if point == 7 or point == 11:
        outcome = OUTCOME_WIN

    elif point == 2 or point == 3 or roll == 12:
        outcome = OUTCOME_LOSE
    else:
        outcome = OUTCOME_REROLL
    return outcome

OUTCOME_WIN = 1
OUTCOME_LOSE = 2
OUTCOME_REROLL = 3

def main():

    bet = enterBet()
    outcome, point = setPoint(bet)

    while outcome == OUTCOME_REROLL:
        outcome = playDice(bet, point)

if __name__ == "__main__":
    main()

下面是我得到的错误：

Please Enter Your Bet: 1
Traceback (most recent call last):
  File "D:/School/CSCI 256/Project 2/p1_2.py", line 43, in <module>
    main()
  File "D:/School/CSCI 256/Project 2/p1_2.py", line 37, in main
    outcome, point = setPoint(bet)
  File "D:/School/CSCI 256/Project 2/p1_2.py", line 13, in setPoint
    point = die1 + die2
NameError: name 'die1' is not defined

Process finished with exit code 1

Answer 1

您没有将rollTheDice的返回值赋给变量，因此解释器不知道die1和die2是什么。这些变量的名称是函数本身的局部变量，因此您也必须在setPoint函数中定义它们。如果将其更改为以下内容：

def setPoint(bet):  # returns the outome of the game and the point
    die1, die2 = rollTheDice()
    point = die1 + die2
    print('You rolled a ' + point + '.')
    print('This is the new point.')
    return point, outcome

它应该知道这些变量。但是，outcome变量仍然存在问题，该变量也没有定义

您似乎返回的点和结果变量的顺序也与预期的不同，因此请注意这一点