擅长:python、mysql、java
<p>您应该使用另一个for循环</p>
<p>顺便说一句,你应该给更容易理解的名单名称,这将是更有效的工作</p>
<pre><code>A = [7, 9, 2, 7, 8, 3, 5, 7, 11, 3, 7]
def mstfrqent(A):
counter = 0
num = A[0]
for i in A:
curr_frequency = A.count(i)
if(curr_frequency> counter):
counter = curr_frequency
num = i
return num
print(mstfrqent(A))
</code></pre>