如何使用python查找列表中最频繁的元素

Question

我想在列表中查找最频繁的元素，但我的代码不起作用。我该怎么办？ 我要走了

**IndentationError: unexpected indent Error

我的代码

A = [7, 9, 2, 7, 8, 3, 5, 7, 11, 3, 7]  
def mstfrqent(A): 
counter = 0
num = A[0] 
for i in A: 
    curr_frequency = A.count(i) 
return i
print(mstfrqent(A))

Answer 1

您应该使用另一个for循环

顺便说一句，你应该给更容易理解的名单名称，这将是更有效的工作

A = [7, 9, 2, 7, 8, 3, 5, 7, 11, 3, 7] 

def mstfrqent(A): 
    counter = 0
    num = A[0] 

    for i in A: 
        curr_frequency = A.count(i) 
        if(curr_frequency> counter): 
            counter = curr_frequency 
            num = i 

    return num 

print(mstfrqent(A)) 

Answer 2

执行下面的代码。似乎你只面临缩进问题，仅此而已

A = [7, 9, 2, 7, 8, 3, 5, 7, 11, 3, 7]  

def mstfrqent(A): 
  counter = 0
  num = A[0] 

  for i in A: 
    curr_frequency = A.count(i) 

  return i


print(mstfrqent(A))