所以我是python新手,一直在尝试创建一个python应用程序来保存.exe文件,然后在“运行”应用程序时打开。在一些youtube教程和这里的一些注释之后,我成功地做到了这一点;然而,我想在我的应用程序中添加一个启动屏幕,我正试图跟随一些示例,但到目前为止启动屏幕还没有显示出来。据我所知,代码应该工作,屏幕本身应该显示,不是说它将工作100%,而是它应该只是显示。我不确定自己做错了什么,需要一些帮助来决定下一步该怎么做;下面是我在尝试实现启动屏幕之前的代码:
import tkinter as tk
from tkinter import filedialog
import os
root = tk.Tk()
root.title("Start My Apps")
apps = []
if os.path.isfile('save.txt'):
with open('save.txt', 'r') as f:
tempApps = f.read()
tempApps = tempApps.split(',')
apps = [x for x in tempApps if x.strip()]
def addApp():
for widget in frame1.winfo_children():
widget.destroy()
filename = filedialog.askopenfilename(initialdir = "/", title="Select File", filetypes = (("executables","*.exe"),("all files" , "*")))
apps.append(filename)
print(filename)
for app in apps:
label1 = tk.Label(frame1, text = app, bg="gray")
label1.pack()
def runApps():
for app in apps:
os.startfile(app)
canvas = tk.Canvas(root, height=700, width=700, bg="#263D42")
canvas.pack(fill="both", expand=True)
frame1 = tk.Frame(root, bg="white")
frame1.place(relwidth = 0.8, relheight = 0.8, relx = 0.1, rely = 0.1)
frame2 = tk.Frame(root, bg="white")
frame2.place(relwidth = 0.8, relheight = 0.05, relx = 0.1, rely = .02)
label2 = tk.Label(frame2, text = "Welcome to: Start My Apps!", font='times 20 bold',bg="white")
label2.pack()
openFile = tk.Button(root, text = "Open File", padx = 10, pady = 5, fg="white", bg="#263D42", command = addApp)
openFile.pack()
runApps = tk.Button(root, text = "Run Apps", padx = 10, pady = 5, fg="white", bg="#263D42", command = runApps)
runApps.pack()
for app in apps:
label1 = tk.Label(frame1, text = app)
label1.pack()
root.mainloop()
with open('save.txt', 'w') as f:
for app in apps:
f.write(app + ',')
代码的第二部分是当我尝试实现启动屏幕时:
import tkinter as tk
from tkinter import filedialog
from tkinter import *
import os
splash_root = Tk()
splash_root.title("Welcome to: Start My Apps!")
splash_root.geometry("700x700")
splash_label = Label(splash_root, text = "Welcome to: Start My Apps!", font='times 20 bold',bg="white")
splash_label.pack(pady=20)
def main_window():
root = Tk()
root.title("Start My Apps")
apps = []
if os.path.isfile('save.txt'):
with open('save.txt', 'r') as f:
tempApps = f.read()
tempApps = tempApps.split(',')
apps = [x for x in tempApps if x.strip()]
def addApp():
for widget in frame1.winfo_children():
widget.destroy()
filename = filedialog.askopenfilename(initialdir = "/", title="Select File", filetypes = (("executables","*.exe"),("all files" , "*")))
apps.append(filename)
print(filename)
for app in apps:
label1 = tk.Label(frame1, text = app, bg="gray")
label1.pack()
def runApps():
for app in apps:
os.startfile(app)
canvas = tk.Canvas(height=700, width=700, bg="#263D42")
canvas.pack(fill="both", expand=True)
frame1 = tk.Frame(bg="white")
frame1.place(relwidth = 0.8, relheight = 0.8, relx = 0.1, rely = 0.1)
frame2 = tk.Frame(bg="white")
frame2.place(relwidth = 0.8, relheight = 0.05, relx = 0.1, rely = .02)
label2 = tk.Label(frame2, text = "Welcome to: Start My Apps!", font='times 20 bold',bg="white")
label2.pack()
openFile = tk.Button(text = "Open File", padx = 10, pady = 5, fg="white", bg="#263D42", command = addApp)
openFile.pack()
runApps = tk.Button(text = "Run Apps", padx = 10, pady = 5, fg="white", bg="#263D42", command = runApps)
runApps.pack()
for app in apps:
label1 = tk.Label(frame1, text = app)
label1.pack()
mainloop()
with open('save.txt', 'w') as f:
for app in apps:
f.write(app + ',')
就像我说的,我对这种编码方式还不熟悉,所以如果你认为还有什么地方是错误的,或者根本没有意义,请告诉我
除非将
Tk()
窗口放在mainloop()
中,否则它不会显示,因此它应该类似于:我之所以使用
splash_root.after()
,是因为它是一个初始屏幕,必须自动销毁,而不是手动销毁。这将在5秒或5000毫秒后关闭启动屏幕这也可以解释为什么
Toplevel()
窗口在使用主窗口的mainloop()
时不需要mainloop()
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