Lambda脚本以获取没有特定标记的实例名称

Question

出于测试目的，我有3个实例，其中2个有标记key:Backup Value:Testing，1个没有这个，我想得到没有这个特定标记的实例名。我正在尝试这种逻辑，即获取所有实例名称，然后查找具有此备份标记的实例，然后从第一个列表中删除第二个列表。我可以同时获得两个列表，但无法从第一个列表中筛选出第二个列表

代码：

import boto3

ec2 = boto3.client('ec2')

def lambda_handler(event, context):
    response = ec2.describe_instances()
    for reservation in response["Reservations"]:
        for instance in reservation["Instances"]:

            print(instance["InstanceId"])


    tags_NV = ec2.describe_tags(
    Filters = [
        {
            'Name':'resource-type',
            'Values':['instance']
        },
        {
        'Name':'key',
        'Values':['Backup']
        }
    ]
    )

    ami_backuppolicy = {i['ResourceId'] for i in tags_NV['Tags']}
    print(ami_backuppolicy)

输出：

Function Logs:
START RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944 Version: $LATEST

i-05a448daa5823d6af
i-0f79ec69714932e8e
i-058bfa970112e8565

{'i-058bfa970112e8565', 'i-05a448daa5823d6af'}

END RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944
REPORT RequestId: c271c3b3-9c64-4d7b-829f-d34ffcb5e944  Duration: 480.40 ms Billed Duration: 500 ms Memory Size: 128 MB Max Memory Used: 73 MB  Init Duration: 276.17 ms    

Answer 1

下面是一个AWS Lambda函数，它将查找没有给定标记的任何实例：

import boto3

def lambda_handler(event, context):

    ec2_resource = boto3.resource('ec2')

    not_backed_up = []

    for instance in ec2_resource.instances.all():
        if not [tag for tag in instance.tags if tag['Key'] == 'Backup' and tag['Value'] == 'Testing']:
            not_backed_up.append(instance.id)

    print(not_backed_up)