我有一个关于异步请求的问题:
如何动态地将response.json()
保存到文件中
我想发出请求并将响应保存到.json
文件,而不将其保存在内存中
import asyncio
import aiohttp
async def fetch(sem, session, url):
async with sem:
async with session.get(url) as response:
return await response.json() # here
async def fetch_all(urls, loop):
sem = asyncio.Semaphore(4)
async with aiohttp.ClientSession(loop=loop) as session:
results = await asyncio.gather(
*[fetch(sem, session, url) for url in urls]
)
return results
if __name__ == '__main__':
urls = (
"https://public.api.openprocurement.org/api/2.5/tenders/6a0585fcfb05471796bb2b6a1d379f9b",
"https://public.api.openprocurement.org/api/2.5/tenders/d1c74ec8bb9143d5b49e7ef32202f51c",
"https://public.api.openprocurement.org/api/2.5/tenders/a3ec49c5b3e847fca2a1c215a2b69f8d",
"https://public.api.openprocurement.org/api/2.5/tenders/52d8a15c55dd4f2ca9232f40c89bfa82",
"https://public.api.openprocurement.org/api/2.5/tenders/b3af1cc6554440acbfe1d29103fe0c6a",
"https://public.api.openprocurement.org/api/2.5/tenders/1d1c6560baac4a968f2c82c004a35c90",
)
loop = asyncio.get_event_loop()
data = loop.run_until_complete(fetch_all(urls, loop))
print(data)
目前,该脚本只打印JSON文件,我可以在它们全部被删除后保存它们:
data = loop.run_until_complete(fetch_all(urls, loop))
for i, resp in enumerate(data):
with open(f"{i}.json", "w") as f:
json.dump(resp, f)
但我觉得它不对,因为它肯定会失败,例如,一旦我的内存用完
有什么建议吗
把我的帖子限制在一个问题上
首先不要使用
response.json()
,而是使用streaming API:相关问题 更多 >
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