如何在python中向flaskrestful添加参数？

Question

如何创建api调用来执行以下操作：

api.add_resource(MyResource, '/myresource/<myurlparameter>')

我不清楚如何从内部处理：

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另外，我注意到我只能将_资源添加到一个级别：

api.add_resource(MyResource, '/myresource') # this works
api.add_resource(MyResource, '/myresource/test') # this this not work

Answer 1

您可以在docs中找到所需的所有内容。在

Parameter in requests

class TodoSimple(Resource):
    def get(self, todo_id):
        return {todo_id: todos[todo_id]}

    def put(self, todo_id):
        todos[todo_id] = request.form['data']
        return {todo_id: todos[todo_id]}

api.add_resource(TodoSimple, '/<string:todo_id>')

Few endpoints

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