给我的问题是:
#Write a script that uses a web API to create a social media post.
#There is a tweet bot API listening at http://127.0.0.1:8082, GET / returns basic info about the API.
#POST / with x-api-key:tweetbotkeyv1 and data with user tweetbotuser and a status-update of alientest.
我的代码回应说我没有提供x-api-key,但它在头中。我的代码:
#
# Tweet bot API listening at http://127.0.0.1:8082.
# GET / returns basic info about api. POST / with x-api-key:tweetbotkeyv1
# and data with user tweetbotuser and status-update of alientest
#
import urllib.parse
import urllib.request
data = urllib.parse.urlencode({
"x-api-key": "tweetbotkeyv1",
"connection": "keep-alive",
"User-agent": "tweetbotuser",
"status-update": "alientest"
})
url = "http://127.0.0.1:8082"
data = data.encode("ascii")
with urllib.request.urlopen(url, data) as f:
print(f.read().decode("utf-8"))
返回:
{"success": "false", "message":"x-api-key Not provided", "flag":""}
标题有问题吗
必须严格按照以下顺序提交url、参数和标题:
urllib.request.Request(url, post_param, header)
结果将是:{"success": "true", "message":"Well done", "flag":"<the flag will be show here>"}
这是可行的解决方案
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