在pygame中使用多行渲染文本

Question

我正在尝试制作一个游戏，我正在尝试渲染大量文本。当文本呈现时，其余文本将离开屏幕。有没有简单的方法让文本进入pygame窗口的下一行

helpT = sys_font.render \
                ("This game is a combination of all of the trends\n of 2016. When you press 'Start Game,' a menu will pop up. In order to beat the game, you must get a perfect score on every single one of these games.",0,(hecolor))
        screen.blit(helpT,(0, 0))

Answer 1

在pygame中，没有简单的方法可以在多行上呈现文本，但是这个助手函数可以为您提供一些帮助。只需输入文本（带换行符）、x、y和字体大小

def render_multi_line(text, x, y, fsize)
        lines = text.splitlines()
        for i, l in enumerate(lines):
            screen.blit(sys_font.render(l, 0, hecolor), (x, y + fsize*i))

Answer 2

正如我在评论中所说；您必须分别渲染每个单词，并计算文本的宽度是否会扩展曲面（或屏幕）的宽度。下面是一个例子：

import pygame
pygame.init()


SIZE = WIDTH, HEIGHT = (1024, 720)
FPS = 30
screen = pygame.display.set_mode(SIZE, pygame.RESIZABLE)
clock = pygame.time.Clock()


def blit_text(surface, text, pos, font, color=pygame.Color('black')):
    words = [word.split(' ') for word in text.splitlines()]  # 2D array where each row is a list of words.
    space = font.size(' ')[0]  # The width of a space.
    max_width, max_height = surface.get_size()
    x, y = pos
    for line in words:
        for word in line:
            word_surface = font.render(word, 0, color)
            word_width, word_height = word_surface.get_size()
            if x + word_width >= max_width:
                x = pos[0]  # Reset the x.
                y += word_height  # Start on new row.
            surface.blit(word_surface, (x, y))
            x += word_width + space
        x = pos[0]  # Reset the x.
        y += word_height  # Start on new row.


text = "This is a really long sentence with a couple of breaks.\nSometimes it will break even if there isn't a break " \
       "in the sentence, but that's because the text is too long to fit the screen.\nIt can look strange sometimes.\n" \
       "This function doesn't check if the text is too high to fit on the height of the surface though, so sometimes " \
       "text will disappear underneath the surface"
font = pygame.font.SysFont('Arial', 64)

while True:

    dt = clock.tick(FPS) / 1000

    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            quit()

    screen.fill(pygame.Color('white'))
    blit_text(screen, text, (20, 20), font)
    pygame.display.update()

结果

Answer 3

这将类似于其他人发布的内容，但我想我也应该上传自己的代码：

    def box_text(surface, font, x_start, x_end, y_start, text, colour):
        x = x_start
        y = y_start
        words = text.split(' ')

        for word in words:
            word_t = font.render(word, True, colour)
            if word_t.get_width() + x <= x_end:
                surface.blit(word_t, (x, y))
                x += word_t.get_width() + 2
            else:
                y += word_t.get_height() + 4
                x = x_start
                surface.blit(word_t, (x, y))
                x += word_t.get_width() + 2

我认为这是不言自明的，你输入你想要的文本开始的位置（x_start）和应该结束的位置，然后它几乎下降，直到你输入的字符串完成

我在个人项目中使用的示例：

x_start = self.W / 2 - info_box.get_width() / 2 + 10

self.box_text(self.WINDOW, self.info_font, x_start, x_start + 430, self.H / 3 + 10, self.mage_text, self.white)

如果你想让文本合理，你必须做一些小的修改