我正在使用Tkinter创建一个游戏,我在通过第一个窗口时,在赋值之前引用了局部变量'num',但我已经将num设置为全局变量。我本来想用我的函数来实现它,但是tkinter不允许我这么做,并且给了我一个错误
from tkinter import *
global num
num = 1.0
def situation_1_1():
if num == 1.0:
window10.destroy()
num = 1.1
global window11
window11 = Tk()
window11.title( " " )
window11.resizable( 0, 0 )
img1 = PhotoImage( file = "img_1_0.png" )
Img_1 = Label( window11, image = img1)
Label_1 = Label( window11, relief = "groove", width = 50 )
Btn_1 = Button( window11, text = "Look around", command = situation_1_1)
Btn_2 = Button( window11, text = "Go out front", command = situation_1_2)
Img_1.grid( row = 1, column = 1, rowspan = 75, columnspan = 75 )
Label_1.grid( row = 1, column = 76, rowspan = 50, columnspan = 100, padx = ( 10, 10 ) )
Btn_1.grid( row = 61, column = 76, columnspan = 50 )
Btn_2.grid( row = 61, column = 126, columnspan = 50 )
Label_1.configure( text = """ """ )
window11.mainloop()
def situation_1_0(num):
num = 1.0
global window10
window10 = Tk()
window10.title( " " )
window10.resizable( 0, 0 )
img1 = PhotoImage( file = "img_1_0.png" )
Img_1 = Label( window10, image = img1)
Label_1 = Label( window10, relief = "groove", width = 50 )
Btn_1 = Button( window10, text = "Explore the house", command = situation_1_1)
Btn_2 = Button( window10, text = "Go round back", command = situation_1_2)
Img_1.grid( row = 1, column = 1, rowspan = 75, columnspan = 75 )
Label_1.grid( row = 1, column = 76, rowspan = 50, columnspan = 100, padx = ( 10, 10 ) )
Btn_1.grid( row = 61, column = 76, columnspan = 50 )
Btn_2.grid( row = 61, column = 126, columnspan = 50 )
Label_1.configure( text = """ """)
window10.mainloop()
situation_1_0(num)
当您尝试为外部作用域中的变量指定新值时,需要在函数中添加全局关键字
在上面的示例中,当您将num传递给情况_1_0(..)函数时,num将被视为局部变量。在情境_1_0()中,您定义了对另一个函数情境_1_1()的调用,该函数试图为全局变量分配一个新值,因此您得到一个错误:
local variable 'x' referenced before assignment
。在函数中使用全局变量应该可以解决您的错误您可以使用以下示例检查相同的情况:
本地人();globals()字典可以帮助查看存在哪些变量
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