import re
import math
def encode(n, strng):
for z in range (n):
temp = []
spcPos = []
for i , x in enumerate(strng):
if x == ' ':
spcPos.append(i)
strng = re.sub(' ', '', strng)
for i in range (len(strng)):
temp.append(strng[i - n])
temp2 = []
ezEnu = 0
for i in temp:
if ezEnu in (spcPos):
temp2.append(' ')
ezEnu += 1
temp2.append(i)
ezEnu += 1
temp2 = ''.join(temp2)
temp2 = temp2.split()
temp = []
withSpc = []
withSpc2 = []
oglen = []
for i in temp2:
oglen.append(len(i))
for x in range (math.ceil(n / len(i))):
withSpc.append(i)
withSpc2.append(''.join(withSpc))
withSpc = []
newa = []
for i, x in enumerate(withSpc2):
for y in range(int(oglen[i])):
newa.append(x[y - n])
temp2 = []
ezEnu = 0
for i in newa:
if ezEnu in (spcPos):
temp2.append(' ')
ezEnu += 1
temp2.append(i)
ezEnu += 1
strng = ''.join(temp2)
return(''.join([str(n), ' ', strng]))
如何获取字符串,并使其成为转义序列作为常规字符处理?
我有一个函数encode,它接受一个字符串并对其进行编码。问题是,当我收到带有/in或任何转义序列的字符串时,它会忽略它们,并且不会将其作为要编码的消息的一部分
我无法控制进入函数的字符串,它们是预定义的
据我所知,r“”只适用于新字符串
谢谢:)
根据您的具体需求,您可以检查这是否足以满足您的用例
相关问题 更多 >
编程相关推荐