if语句的代码不工作问题

Question

我的代码有问题，它应该打印“你有一个罕见的姓氏！”或者一个非常罕见的例子，如果你在输入的字符串中有q或q，如果没有，它将不打印q，但它不会打印no q

这里是我的非工作代码：

a = input("What is your surname? ")
d = len(a)
v = ["q", "Q"]
if any(v in a for v in a):
  if a[0] == "Q" :
    if a[0] == ("q"):
      print("You have an extremly rare surname!")
    if a[0] == ("Q"):
      print("You have an extremly rare surname!")
  if a[0] == "q" :
    if a[0] == ("q"):
      print("You have an extremly rare surname!")
    if a[0] == ("Q"):
      print("You have an extremly rare surname!")
  if "q" in a[1:d]:
    print("You have a rare surname!")
else:
  print("No Qs here.")

Answer 1

另一种简化代码的方法是使用^{}将字符串转换为小写，并使用字符串slice检查不带第一个字符的字符串：

rare_letter = 'q'
user_surname = input("What is your surname? ").lower()

if user_surname[0] == rare_letter:
  print("You have an extremly rare surname!")
elif rare_letter in user_surname[1:]:
  print("You have a rare surname!")
else:
  print("No Qs here.")

试试看here!