需要显示正账单和负账单

Question

大家好，有些VAR是葡萄牙语的对不起，所以我想展示一下，在atm机上，你会和不会得到多少威奇类型的钞票：例如：

IN: $123,45

OUT:1 OF $100 BILL, 0 OF $50 BILL, 1 OF $20 BILL, 0 OF $10 BILL and etc.

这是我到目前为止所做的，但我不能做的法案，将不会在自动取款机请帮助

r = 0
print('='*20)
print('{:^20}'.format('CAIXA ELETRÔNICO'))
print('{:^20}'.format(' Banco do Romeu '))
print('='*20)

caixa = float(input('Qual será o valor sacado? '))
total = caixa
ced = 100
totalced = 0

while True:

    if total >= ced:
        total = total - ced
        totalced += 1

    else:
        if totalced > 0:
            print(f'{totalced} notas(s) de R${ced}')

        elif ced == 100:
            ced = 50
        elif ced == 50:
            ced = 20
        elif ced == 20:
            ced = 10
        elif ced == 10:
            ced = 5
        elif ced == 5:
            ced = 2
        elif ced == 2:
            ced = 1
        elif ced == 1:
            ced = 0.50
        elif ced == 0.50:
            ced = 0.25
        elif ced == 0.25:
            ced = 0.10
        elif ced == 0.10:
            ced = 0.05
        elif ced == 0.05:
            ced = 0.01
        totalced = 0

        if total == 0:
            break

Answer 1

可以从初始值中减去值。 变量valor是初始值

valor = 162
cells = []
money = [100, 50, 20, 10, 5, 2]

for _ in money:

    while True:

        if valor >= _:        
            if valor - _ < money[-1] or (valor % _) % money[-1] != 0:
                if valor == _:
                    cells.append(_)
                break
            valor -= _
            cells.append(_)

        else:
            break

print(cells)

>>> [100, 50, 10, 2]

Answer 2

你可以做一个贪婪的方法，试着减去价值最高的账单，并记下你从每张账单中减去的次数。例如：

423,45岁

从100美元开始，你可以减去4倍。你只剩下23，45了。 然后你继续付50美元。你不能从23，45减去50美元，所以你要付次高的20美元。 你可以从23，45减去一美元20，剩下的是，45

你继续数到不能再减法为止。然后你打印出每张账单的减法数。希望这有道理