从文本文件替换目录中的文件名

Question

我想使用Python从包含“target”名称的.txt文件重命名名为myShow的目录中的文件：

realNameForEpisode1
realNameForEpisode2
realNameForEpisode3

层次结构如下所示：

episodetitles.txt
myShow
├── ep1.m4v
├── ep2.m4v
└── ep3.m4v

我尝试了以下方法：

import os

with open('episodetitles.txt', 'r') as txt:
    for dir, subdirs, files in os.walk('myShow'):
        for f, line in zip(sorted(files), txt):

            originalName = os.path.abspath(os.path.join(dir, f))
            newName = os.path.abspath(os.path.join(dir, line + '.m4v'))
            os.rename(originalName, newName)

但我不知道为什么在扩展名之前的文件名末尾有一个?：

realNameForEpisode1?.m4v
realNameForEpisode2?.m4v
realNameForEpisode3?.m4v

Answer 1

只需导入“操作系统”即可：

import os
with open('episodes.txt', 'r') as txt:
    for dir, subdirs, files in os.walk('myShow'):
        for f,line in zip(sorted(files), txt):
            if f == '.DS_Store':
               continue
            originalName = os.path.abspath(os.path.join(dir, f))
            newName = os.path.abspath(os.path.join(dir, line + '.m4v'))
            os.rename(originalName, newName)