<p>如果必须排序,请将键映射到整数,然后使用该映射进行排序:</p>
<pre><code>id_to_pos = {key: i for i, key in enumerate(req_ids)}
sorted(res_result, key=lambda d: id_to_pos[d['id']])
</code></pre>
<p>演示:</p>
<pre><code>>>> from pprint import pprint
>>> req_ids = ['964', '123', '534', '645', '876', '222']
>>> res_result = [{'id':'123', 'name':'Sachin'},
... {'id':'534', 'name':'Vipin'},
... {'id':'222', 'name':'Ram'},
... {'id':'645', 'name':'Anoop'},
... {'id':'964', 'name':'Sani'},
... {'id':'876', 'name':'John'}]
>>> id_to_pos = {key: i for i, key in enumerate(req_ids)}
>>> sorted(res_result, key=lambda d: id_to_pos[d['id']])
[{'id': '964', 'name': 'Sani'}, {'id': '123', 'name': 'Sachin'}, {'id': '534', 'name': 'Vipin'}, {'id': '645', 'name': 'Anoop'}, {'id': '876', 'name': 'John'}, {'id': '222', 'name': 'Ram'}]
>>> pprint(_)
[{'id': '964', 'name': 'Sani'},
{'id': '123', 'name': 'Sachin'},
{'id': '534', 'name': 'Vipin'},
{'id': '645', 'name': 'Anoop'},
{'id': '876', 'name': 'John'},
{'id': '222', 'name': 'Ram'}]
</code></pre>
<p>但是,您可以完全避免排序,您已经有了正确的顺序,只需从<code>id</code>键映射到字典(O(N)),然后按正确的顺序拉出字典(仍然是O(N)):</p>
<pre><code>id_to_dict = {d['id']: d for d in res_result}
[id_to_dict[id] for id in req_ids]
</code></pre>
<p>演示:</p>
<pre><code>>>> id_to_dict = {d['id']: d for d in res_result}
>>> [id_to_dict[id] for id in req_ids]
[{'id': '964', 'name': 'Sani'}, {'id': '123', 'name': 'Sachin'}, {'id': '534', 'name': 'Vipin'}, {'id': '645', 'name': 'Anoop'}, {'id': '876', 'name': 'John'}, {'id': '222', 'name': 'Ram'}]
>>> pprint(_)
[{'id': '964', 'name': 'Sani'},
{'id': '123', 'name': 'Sachin'},
{'id': '534', 'name': 'Vipin'},
{'id': '645', 'name': 'Anoop'},
{'id': '876', 'name': 'John'},
{'id': '222', 'name': 'Ram'}]
</code></pre>