将字典列表中的元素添加到另一个

Question

dict_1 = [
        {'INCIDENT_ID': 'SD000001372596', 'FIRST_CALL': 't'}
        {'INCIDENT_ID': 'SD000001372594', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372598', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372599', 'FIRST_CALL': 't'}
        {'INCIDENT_ID': 'SD000001372602', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372601', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372605', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372606', 'FIRST_CALL': 'f'}
        {'INCIDENT_ID': 'SD000001372607', 'FIRST_CALL': 'f'}
    ]

dict_2 = [
        {'INCIDENT_ID': 'SD000001372605', 'DATE': '08-10-2016 00:54:13'}
        {'INCIDENT_ID': 'SD000001372606', 'DATE': '08-10-2016 00:57:20'}
        {'INCIDENT_ID': 'SD000001372607', 'DATE': '08-10-2016 01:00:25'}
        {'INCIDENT_ID': 'SD000001372598', 'DATE': '11-10-2016 10:57:34'}
        {'INCIDENT_ID': 'SD000001372602', 'DATE': '08-10-2016 10:44:34'}
        {'INCIDENT_ID': 'SD000001372601', 'DATE': '21-10-2016 22:30:49'}
        {'INCIDENT_ID': 'SD000001372594', 'DATE': '18-10-2016 14:53:34'}
]

我有两个不同长度的字典列表，我想根据“事件ID”将（“dict\u 2”日期）添加到“dict\u 1”中

Answer 1

您可以使用来自collections模块的defaultdict：

from collections import defaultdict

dct = defaultdict(dict)
for i in zip(dict_1, dict_2):
  for j in i:
    dct[j["INCIDENT_ID"]].update(j)
solution_dict = list(dct.values())

因此，现在solution_dict将为您提供具有组合对的词典列表：

[ {'INCIDENT_ID' : 'SD000001372607', 'DATE': '08-10-2016 01:00:25'}
{'INCIDENT_ID': 'SD000001372601', 'DATE': '21-10-2016 22:30:49', 'FIRST_CALL': 'f'}
{'INCIDENT_ID': 'SD000001372606', 'DATE': '08-10-2016 00:57:20'}
{'INCIDENT_ID': 'SD000001372598', 'DATE': '11-10-2016 10:57:34', 'FIRST_CALL': 'f'}
{'INCIDENT_ID': 'SD000001372596', 'FIRST_CALL': 't'}
{'INCIDENT_ID': 'SD000001372594', 'DATE': '18-10-2016 14:53:34', 'FIRST_CALL': 'f'}
{'INCIDENT_ID': 'SD000001372605', 'DATE': '08-10-2016 00:54:13', 'FIRST_CALL': 'f'}
{'INCIDENT_ID': 'SD000001372599', 'FIRST_CALL': 't'}
{'INCIDENT_ID': 'SD000001372602', 'DATE': '08-10-2016 10:44:34', 'FIRST_CALL': 'f'} ]