subprocess.Popen（[“open”，“target.mkv”]，shell=True打开指定fi失败

Question

我正在学习subprocess打开多媒体“.mkv”文件

首先，我测试：

In [25]: subprocess.Popen(
    ...:     ["open", "/Volumes/Transcend/Downloads/The.Adventure.of.English.Ep4.mkv"], shell=True)
    ...:     
Out[25]: <subprocess.Popen at 0x10b063908>
In [26]: Usage: open [-e] [-t] [-f] [-W] [-R] [-n] [-g] [-h] [-s <partial SDK name>][-b <bundle identifier>] [-a <application>] [filenames] [--args arguments]

所发生的只是提示使用信息

然后，我试着：

In [27]: subprocess.Popen('open "/Volumes/Transcend/Downloads/The.Adventure.of.English.Ep4.mkv"', shell=True)
Out[27]: <subprocess.Popen at 0x10b114208>

它成功了，立即打开了目标文件

我注意到[]的第一个选项比后面的“string”选项更可取

[]选项打开文件失败有什么问题

Answer 1

从subprocess.Popen构造函数（Docs）中：

The shell argument (which defaults to False) specifies whether to use the shell as the program to execute. If shell is True, it is recommended to pass args as a string rather than as a sequence.