try:/except:尝试运行modu时返回Python中的语法错误

Question

下面是我的代码和错误是在第4行“除了”给出了一个语法错误(这是一个调试和错误捕获分配。我看不出有什么问题）

while True:
        try:
                userInputOne = input(int("How much time in hours a week, do you spend practicing? ")
        except TypeError:
                print("Oops! Practice time must be rounded to the nearest integer. It also needs to be a numerical value! ")
                break
    else:
        userInputTwo = str(input"How good to do want to be? Enter 'very good', 'good', mediocre, 'not good' ")
        if userInputTwo not in ('very good', 'good', 'mediocre', 'not good'):
            print("Please use one of the options. ")
        else:
            print("Let's calculate...")
            break

Answer 1

我附上了工作代码。 语法错误是由于缺少排列和错误的缩进造成的。看看你的else:语句。它与try:语句的高度不同。 TypeError的意思是，你不必把你的输入转换成字符串，因为它们已经是了。否则，我建议您创建一些变量，并在使用它们进行计算时通过int()转换它们

while True:
    try:
        userInputOne = input("How much time in hours a week, do you spend practicing? ")
    except TypeError:
        print("Oops! Practice time must be rounded to the nearest integer. It also needs to be a numerical value! ")
        break
    else:
        userInputTwo = input("How good to do want to be? Enter 'very good', 'good', mediocre, 'not good' ")
        if userInputTwo not in ('very good', 'good', 'mediocre', 'not good'):
            print("Please use one of the options. ")
        else:
            print("Let's calculate...")
            break

编辑： 我建议使用PyCharm（如果你不这样做的话）的自动缩进功能和不错的“缩进准则”。所以你可以更容易地看到许多错误