擅长:python、mysql、java
<p>您可以使用<code>itertools.zip_longest</code>如<a href="https://stackoverflow.com/questions/58291325/creating-a-list-where-each-listj-is-the-character-j-from-each-element-in-anoth#comment102947100_58291325">@juanpa.arrivillaga</a>在注释中所述:</p>
<pre><code>list(map(''.join, zip_longest(*list1, fillvalue='')))
</code></pre>
<p>或手动:</p>
<pre><code>result = [''] * max(map(len, list1))
for i in range(len(result)):
for s in list1:
if i < len(s): result[i] += s[i]
</code></pre>