#import numpy as np
from random import randrange
Matrix = [[randrange(10) for x in range(5)] for z in range(5)]
def triu(matrix):
length = len(matrix[0])
U = list()
diagLine = 0
for row in Matrix:
length -= 1
colCounter = 0
for col in row:
if colCounter > diagLine:
U.append(col)
colCounter += 1
diagLine += 1
return U
#print np.matrix(Matrix)
print triu(Matrix)
from random import randrange
Matrix = [[randrange(10) for x in range(5)] for z in range(5)]
>>>Matrix
[[6, 3, 7, 9, 3], [8, 6, 4, 0, 4], [0, 0, 1, 3, 2], [7, 7, 2, 3, 7], [3, 3, 5, 6, 3]]
[Matrix[i][j] for i in range(0,5) for j in range(i+1,5)]
[3, 7, 9, 3, 4, 0, 4, 3, 2, 7]
所以这里有一个解决方案,我改变了你的矩阵来生成任意的随机数,这样你就可以更好地看到哪些数字被考虑进去了。TRIU=Triangle Upper是一个函数,它采用给定格式的矩阵,并采用对角线上方的上三角形
结果:
你可以只使用列表理解
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