正则表达式：用条件替换子字符串

Question

我有文本，这是一个例子

[04.1_Filialy 680031, Khabarovsk Territory, Khabarovsk, ul. District, 6, building b, office 3.] and [04.1_OGRN660050463454]

期望输出

<address> 680031, Khabarovsk Territory, Khabarovsk, ul. District, 6, building b, office 3.<\address> and [04.1_OGRN660050463454]

我需要如果str中的re.findall(r'\[[\d\.]+_(?:Filialy|MN)[^]]+]，将第一个r'\[[\d\.]+_(?:Filialy|MN)'和r']'替换为<address>和<\address>

我该怎么做

Answer 1

将[^]]+放入捕获组()并使用re.sub()

正则表达式：^{}替换：<address>\1<\\address>

Python代码：

re.sub(r'\[[\d\.]+_(?:Filialy|MN)([^]]+)\]', r'<address>\1<\\address>', str)

输出：

<address> 680031, Khabarovsk Territory, Khabarovsk, ul. District, 6, building b, office 3.<\address> and [04.1_OGRN660050463454]

Code demo