如何修复此代码以发送到#报告

Question

一个相对简单的命令，它有3个参数（reportedTag、reporterTag和reasons），目的很简单，就是从#report中删除消息并发送一个到#reported我的问题是它看不到原始命令，因此不发送报告的消息

我试过使用频道ID，频道名称，但是没有用

#---Report Command---#
@bot.command(pass_context=True)
async def report(ctx,  reportedTag, reporterTag, *reasons):

  if int(ctx.message.channel.id) == 416164062901305345:
    reason = ' '.join(reasons)
    await bot.delete_message(ctx.message)   
    mesg = "Report by "+ reporterTag +  " for " + reportedTag + "Reason is: " + reason
    return await bot.say("Report recieved. Staff have been notified :)\nEnjoy your day and we'll take care of this")
    return await bot.send_message(bot.get_channel("534496148149370900"), mesg)
  else:
      print ("Something went wrong")  

预期结果：命令行从#报告中删除，消息发送到#报告

实际结果：“出事了”

Answer 1

有两件事不对：

在代码中使用的return语句中有一个问题return退出子例程，因此bot.send_message(bot.get_channel("534496148149370900"), mesg)行实际上从未被调用。所以你的代码应该改成这样：

# -Report Command -#
@bot.command(pass_context=True)
async def report(ctx,  reportedTag, reporterTag, *reasons):

if int(ctx.message.channel.id) == 416164062901305345:
    reason = ' '.join(reasons)
    await bot.delete_message(ctx.message)   
    mesg = "Report by "+ reporterTag +  " for " + reportedTag + "Reason is: " + reason
    await bot.send_message(bot.get_channel("534496148149370900"), mesg)
    return await bot.say("Report recieved. Staff have been notified :)\nEnjoy your day and we'll take care of this")
else:
    print ("Something went wrong") 

除此之外，如果“出事了”实际上是输出的，那就意味着int(ctx.message.channel.id) == 416164062901305345是假的。请检查你的身份证和你正在写的频道