用python返回值

Question

当前结果返回

 [['jackson', ['21', '22'], ['20','24']], ['barkley', ['30', '32'], ['33', '34']]]

我想把这些值分开

   a = jackson, barkley
   b = (jackson, 21), (jackson, 22), (jackson, 23), (jackson 24), (barkley, 30)..etc

最好的办法是什么？谢谢

Answer 1

>>> d = [['jackson', ['21', '22'], ['20','24']], ['barkley', ['30', '32'], ['33', '34']]]
>>> [(i[0],z) for i in d for j in i[1:] for z in j]
[('jackson', '21'), ('jackson', '22'), ('jackson', '20'), ('jackson', '24'), ('barkley', '30'), ('barkley', '32'), ('barkley', '33'), ('barkley', '34')]

你只需遍历它，然后遍历子列表。。。好的没问题：P