用BeatifulSoup解析HTML中的文本块（IndustryAbout）

Question

我想解析来自industryAbout的矿山条目。在这个例子中，我正在处理Kevitsa Copper Concentrator

HTML中有趣的块是：

<strong>Commodities: Copper, Nickel, Platinum, Palladium, Gold</strong><br /><strong>Area: Lappi</strong><br /><strong>Type: Copper Concentrator Plant</strong><br /><strong>Annual Production: 17,200 tonnes of Copper (2015), 8,800 tonnes of Nickel (2015), 31,900 tonnes of Platinum, 25,100 ounces of Palladium, 12,800 ounces of Gold (2015)</strong><br /><strong>Owner: Kevitsa Mining Oy</strong><br /><strong>Shareholders: Boliden AB (100%)</strong><br /><strong>Activity since: 2012</strong>

我已经编写了一个（基本的）工作解析器，它

<strong>Commodities: Copper, Nickel, Platinum, Palladium, Gold</strong>
<strong>Area: Lappi</strong>
<strong>Type: Copper Concentrator Plant</strong>
....

但我想把$commodities、$type、$annual\u production、$partners和$activity作为单独的变量。我该怎么做？正则表达式

import requests
from bs4 import BeautifulSoup
import re

page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/34519-kevitsa-copper-concentrator-plant") 
soup = BeautifulSoup(page.content, 'lxml')

rows = soup.select("strong")

for r in rows:
    print(r)

第2版：

import requests
from bs4 import BeautifulSoup
import re
import csv

links = ["34519-kevitsa-copper-concentrator-plant", "34520-kevitsa-copper-mine", "34356-glogow-copper-refinery"]

for l in links:

    page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/"+l)
    soup = BeautifulSoup(page.content, 'lxml')
    rows = soup.select("strong")
    d = {}

    for r in rows:
        name, value, *rest = r.text.split(":")
        if not rest:
            d[name] = value
    print(d)

Answer 1

这是你想要的吗

import requests
from bs4 import BeautifulSoup

page = requests.get("https://www.industryabout.com/country-territories-3/2199-finland/copper-mining/34519-kevitsa-copper-concentrator-plant")
soup = BeautifulSoup(page.content, 'html.parser')

rows = soup.select("strong")
d = {}
for r in rows:
    name, value, *rest = r.text.split(":")
    if not rest: # links or scripts have more ":" probably not intesting for you
        d[name] = value
print(d)