擅长:python、mysql、java
<p>正在添加到Navith的解决方案索引</p>
<pre><code>def get_nested_index(list_, element):
lt = []
for index, container in enumerate(list_):
if element in container:
t = index, container.index(element)
lt.append(t)
t = ()
return lt
print(get_nested_index([(0, 1, 4, 2), (3, 4, 5)], 4))
</code></pre>
<p>输出
[(0,2),(1,1)]</p>