def get_nested_index(list_, element):
for index, container in enumerate(list_):
if element in container:
return index
# If we made it here, it wasn't in any of the containers
raise ValueError("{element} not in any element in list".format(element=element))
def get_nested_index(list_, element):
lt = []
for index, container in enumerate(list_):
if element in container:
t = index, container.index(element)
lt.append(t)
t = ()
return lt
print(get_nested_index([(0, 1, 4, 2), (3, 4, 5)], 4))
在列表中的容器中搜索元素:
-
如果你以前没看过的话,你可以看看^{} here
正在添加到Navith的解决方案索引
输出 [(0,2),(1,1)]
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