这个代码似乎不起作用为什么我不明白

Question

我试着做一个程序，电脑从列表中随机选取一个单词，然后把这个单词的字母乱序排列，结果它不起作用。为什么不起作用

import random
mysports= ["swimming" , "basketball" , "soccer" , "cross country" , 
"football" , "cross-country skiing"]
letters = mysports[0]
letters1 = mysports[1]
letters2 = mysports[2]
letters3 = mysports[3]
letters4 = mysports[4]
letters5 = mysports [5]
a = (random.choice(mysports)) 
if a == mysports[0]:
   b = random.shuffle(letters)
   print (b)
elif a == mysports[1]:
   c = random.shuffle(letters1)
   print (c)
elif a == mysports[2]:
   d = random.shuffle(letters2)
   print (d)
elif a == mysports[3]:
   e = random.shuffle(letters3)
   print (e)
elif a == mysports[4]:
   f = random.shuffle(letters4)
   print (f)
elif a == mysports[5]:
   g = random.shuffle(letters5)
   print (g)

当我试着运行它时，它给了我这样的信息：

Traceback (most recent call last): File "python", line 23, in TypeError: 'str' object does not support item assignment

Answer 1

random.shuffle（）只能洗牌列表。要做你想做的事，你必须把这个单词的字母变成一个列表

我建议你这样做

import random
mysports= ["swimming" , "basketball" , "soccer" , "cross country" , 
"football" , "cross-country skiing"]
letters = mysports[0]
letters1 = mysports[1]
letters2 = mysports[2]
letters3 = mysports[3]
letters4 = mysports[4]
letters5 = mysports [5]
a = random.choice(mysports)
aList = []
for char in a:
    aList.extend(char)
random.shuffle(aList)
aString = ""
for char in aList:
    aString += char
print(aString)

它会做你想做的，而且效率更高