擅长:python、mysql、java
<p>也许这样就可以了-假设你想要c的值作为浮点列表,假设a的值总是一个元素列表…:</p>
<pre><code>a = {'SITE1': [700], 'SITE2': [500]}
b = {'SITE1': [1,2,3,4], 'SITE2': [4,5,6,7], 'SITE3': [8,9,10,11]}
c = dict()
for key in b:
if key in a:
c[key] = [float(v)/(a[key][0]) for v in b[key]]
else:
c[key] = [0 for v in b[key]]
</code></pre>