我有一个RESTAPI端点,它以JSON格式返回可用国家的列表,如:
[["ALL","Albania Lek"],["AFN","Afghanistan Afghani"],["ARS","Argentina Peso"],["AWG","Aruba Guilder"],["AUD","Australia Dollar"]]
我需要把它转换成
{
"ALL":"Albania Lek",
"AFN":"Afghanistan Afghani",
"ARS":"Argentina Peso"
}
如何快速有效地完成此任务
Tags:
我想
比dict(the\ u list)好,因为它不调用函数。因此,性能明智的理解获胜
参见测试:https://doughellmann.com/blog/2012/11/12/the-performance-impact-of-using-dict-instead-of-in-cpython-2-7-2/
以及: https://medium.com/@jodylecompte/dict-vs-in-python-whats-the-big-deal-anyway-73e251df8398
dict()
构造函数直接从键值对序列构建字典,如documentation中所述。就这么简单:另一个1行选择是dict理解
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