如何在匹配模式后，根据另一个列表中预定义的顺序对文件名列表进行排序？

Question

我正在尝试对光栅列表进行排序（rasters）

 rasters = '["example\\\\alt_canal.tif", "example\\\\back_garden.tif", "example\\\\main_entrance.tif", "example\\\\my_ditch.tif", "example\\\\ne_lawn.tif"]'

基于模式匹配和预定义顺序（ras_order）

ras_order = '["ditch", "canal", "entrance", "garden", "lawn"]'

我遵循这个answer但是它没有给我想要的。感谢您的帮助。谢谢

预期产量：

[u'example\my_ditch.tif', u'example\alt_canal.tif', u'example\main_entrance.tif', u'example\back_garden.tif', u'example\ne_lawn.tif']

示例代码：

import os
import arcpy

arcpy.CheckOutExtension("Spatial")  

# set project directory
working_dir = os.path.expanduser('~/Documents/')
scenario = 'example'
env.workspace = os.path.join(working_dir, scenario)

# predefined order
ras_order = ['ditch', 'canal', 'entrance', 'garden', 'lawn']

# find rasters in the working_dir 
rasters = []  
walk = arcpy.da.Walk(os.path.join(working_dir, scenario), topdown=True, datatype="RasterDataset")  
for dirpath, dirnames, filenames in walk:  
    for filename in filenames:  
        rasters.append(os.path.join(dirpath, filename))  

print(rasters)

# [u'example\\alt_canal.tif', u'example\\back_garden.tif', u'example\\main_entrance.tif', u'example\\my_ditch.tif', u'example\\ne_lawn.tif']

# sort based on predefined order (not working)
new_order1 = [x for _, x in sorted(zip(ras_order, rasters))]
print(new_order1)

# [u'example\\back_garden.tif', u'example\\alt_canal.tif', u'example\\main_entrance.tif', u'example\\my_ditch.tif', u'example\\ne_lawn.tif']

除了@Lante的答案，还有另一种方法：

new_raster = []
for i in ras_order:
    for j in rasters:
        if i in j:
            new_raster.append(j)
new_raster

[u'example\\\\Max (dec).my_ditch.tif',
 u'example\\\\Max (dec).alt_canal.tif',
 u'example\\\\Max (dec).main_entrance.tif',
 u'example\\\\Max (dec).back_garden.tif',
 u'example\\\\Max (dec).ne_lawn.tif']

Answer 1

这是一个简单的解决方案，需要使用regex进行优化，以实现更精确的匹配：

rasters = ["example\\\\alt_canal.tif", "example\\\\back_garden.tif", "example\\\\main_entrance.tif", "example\\\\my_ditch.tif", "example\\\\ne_lawn.tif"]
ras_order = ["ditch", "canal", "entrance", "garden", "lawn"]

def ras_match(r, o):
    return next(i for i, x in enumerate(o) if x in r)

sorted(rasters, key=lambda x: ras_match(x, ras_order))

输出：

['example\\\\my_ditch.tif',
 'example\\\\alt_canal.tif',
 'example\\\\main_entrance.tif',
 'example\\\\back_garden.tif',
 'example\\\\ne_lawn.tif']